4y^2-19y+21=0

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Solution for 4y^2-19y+21=0 equation:


Simplifying
4y2 + -19y + 21 = 0

Reorder the terms:
21 + -19y + 4y2 = 0

Solving
21 + -19y + 4y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(7 + -4y)(3 + -1y) = 0

Subproblem 1

Set the factor '(7 + -4y)' equal to zero and attempt to solve: Simplifying 7 + -4y = 0 Solving 7 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -4y = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -4y = 0 + -7 -4y = 0 + -7 Combine like terms: 0 + -7 = -7 -4y = -7 Divide each side by '-4'. y = 1.75 Simplifying y = 1.75

Subproblem 2

Set the factor '(3 + -1y)' equal to zero and attempt to solve: Simplifying 3 + -1y = 0 Solving 3 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1y = 0 + -3 -1y = 0 + -3 Combine like terms: 0 + -3 = -3 -1y = -3 Divide each side by '-1'. y = 3 Simplifying y = 3

Solution

y = {1.75, 3}

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